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How did you get 3.42uF for the total capacitance?


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for my problem, Vab=26V, c1=2.8uF, c2=5.45uF, c3=5.85uF, I need to find the charge on each capacitor...
C1 & C2 are in parallel so therefore there capacitance adds. So 2.8uF+5.45uF=8.25uF

C1 & C2 are in series with C3 so the total between them is equal to the reciprocal of the sum of the reciprocals,

or 1/((1/8.25)+(1/5.85))=3.422uF
 
Im sure all of you guys could do it, if you were taught how. Its really straight forward.

Cmon some of you guys can take a heap of metal and turn into into a beautiful car, im sure you could crank out some physics problems!
 
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