originally posted by MalibuJerry350..
"Actually, if the resistance was high, the current would decrease. I would look for a LOW resistance path somewhere on the LOAD end of the burnt wire. If none of the fuses under the dash are blown, look for"
True, (E = I X R), but only if you have a purely resistive car, with no Power supplies (Stereo, etc), no motors (Electric fans, etc), and no LC circuits (coil, etc). If this describes your car, and it runs, I really want to see it.
Let me explain my point, if you have a motor or Power Supply (example: Stereo system) that uses or pulls 6 amps (at 12 Vdc). It's rated power in watts very close to 72. Now you have a bad connection (whatever it may be) in the line that drops 4 Vdc. The load now still wants it's 72 watts, but it only has 8 volts to work with. This is true for almost all Power Supplies and Motors (but not all, ofcourse). Therefore, P = I X E, Voltage has dropped, current must increase to 9 amps to maintain the 72 watts. Since all cars have motors and Power Supplies, this was my thinking when I made the above statement.
Regards,
SS4speed.