[Partel Roos]

hey i have seen it somewhere sometime, but can not find. Of course I can do a little research and calculate it by myself but just be be sure...

Thanks.
Partel.

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Partel Roos
Tallinn, Estonia, Europe
Law Student, Tartu University (a.d. 1632)
GSM cell ph: +37 250 93828

 

[68Malibu Blown 406]

Using .5 as a generic amount (lb) of fuel it takes to sustain 1 Hp for 1 hour, you multiply this number times your horsepower (i.e. 200 X .5 = 100 this is how many lbs. it takes to sustain 200 Hp for 1 hour. Now you have to convert the weight, into volume.
So gas being about 6 Lbs/gallon, we divide 100 lbs by 6 to give the number of gallons.
100 / 6 = 16.6 or 16.6 gallons per hour to sustain 200 HP.


HTH


[This message has been edited by 68Malibu Blown 406 (edited 11-10-99).]

 

[Bryan]

Neat formula! I've been trying to figure that for a long time.
Questions, HTH:
What do you mean by "generic amount/.5lb"?
Is .5lb an actual number or just an example you were using to illustrate the formula?
Would that number(.5) vary depending on octane, barometric pressure or anything else?
If so, can you describe the adjustments that must be made to this formula to compensate?
Thanks for info, Bryan

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'65 Malibu frame-off project(slow going!)
'70 C-20 Longhorn p/u (daily driver)