Given the equation S1 = S0 + V0*t + 1/2 a * t *t where S0 is inititial position (0 ft), S1 is current position (60 ft), V0 is initial velocity (0 ft/sec), t is time in seconds and a is acceleration, you can reduce the equation and solve for a = 120 / (t*t). Then since the acceleration of gravity is 32 ft per second squared, g = a / 32 or 3.75 / (t * t). This only works if you assume that the vehicle accelerates at a constant rate though...