I understand the concept of the lambda # and that a wideband converts it to an A/F #.
But if the computer thinks you are running E0 isn't it converting from a base of 14.7/1 ?
It doesn't know it is seeing E10, and change the basis of the calculation, so you would need to adjust the target to compensate, right? What you are saying seems counter - intuitive. I mean, you can't calculate a correct ratio for one fuel when using the numbers for a different fuel?
(remember, I am just trying to learn, not argue!)
John