: hp = torque x rpm / 5252
Horsepower69 May 1st, 00, 2:38 PM hp = torque x rpm /5252....does this formula also apply for high perfromance or modified engines?? Even on a modified engine, are hp and torque always the same??...If i posted this in the wrong forum...i'm sorry....
Thanks for your time,
Pete
Gene Chas May 1st, 00, 2:44 PM "always the same" no but HP is simply a function of torque and the equation you've posted. All dynos measure torque and compute horsepower. Regardless of engine type/config I would assume.
------------------
Chaas
Gold #62/ACES
67 SS396/(427L88) (http://www.chevelles.com/showroom/chaas1.jpg)
Unclepennybags May 1st, 00, 3:03 PM You assumed correctly. This is how we figure it in the manual rooms.
Keith Tedford May 1st, 00, 3:41 PM This only happens at 5252 rpm. At this point the torque and horsepower are equal.
[This message has been edited by Keith Tedford (edited 05-02-2000).]
Unclepennybags May 1st, 00, 5:16 PM This is true for all rpm's. We used to have to calculate our h.p. by hand when we ran a manual dynamometer cell.
Quadzilla May 1st, 00, 7:23 PM whats so damn special abt 5252rpm? for the life of me I can't figure out my that rpm is the magic point.
------------------
Francis Taracido Gold# 201 :)
sniper0666@aol.com
History shows again and again how nature points out the folly of man.
Oh No! You Know She's Got To Go!
Go Go Quadzilla! <oo=+=oo>
http://members.aol.com/sniper0666/page/intro.html
Unclepennybags May 1st, 00, 8:32 PM Lev is right.
To put it another way.....do you remember "pi" from geometry class? If you wanted to find the area of a circle you multiplied the Radius X Radius X pi. In this equation pi (3.14) is a "constant". It did not matter what the size of the circle was, the equation always worked. Similarly, 5252 is a constant used in the formula to find horsepower. Simply multiply observed torque by RPM and divide by 5252. This equation works at any speed.
[This message has been edited by Unclepennybags (edited 05-01-2000).]
Carl Brune May 1st, 00, 8:40 PM Quad, The basic equation, like you would see in a physics textbook, is power = torque * angular velocity. The goofy number comes from unit conversions and the factor 2*pi difference between angular velocity and frequency.
IgnitionMan May 1st, 00, 11:03 PM 5252 rpms is the place both horsepower and torque output cross each other in the rev range at exactly the same output power levels, on every fossil fuel fed, internal combustion engine ever made. All of them.
...As long as torque is measured in ft/lbs!
Fine69 May 2nd, 00, 9:09 AM How would it differ?
<BLOCKQUOTE>quote:</font><HR>Originally posted by lev:...As long as torque is measured in ft/lbs!<HR></BLOCKQUOTE>
------------------
...DjD
69 Ragtop
IgnitionMan May 2nd, 00, 9:36 AM Measurement may be in lbs-ft/hp, kg/m, kp/a or anything else that indicates power levels, as long as both horsepower and torque are measured with the same guideline measuring system. Can't do lbs-ft/m, lbs-ft/a, kg/a or kp/m, etc., doesn't inter-relate.
Unclepennybags May 2nd, 00, 9:53 AM If you want to convert to Newton-Meters just multiply your ft.lb. answer by 1.355
| |